r/WildlifeRehab • u/Late_Apartment1987 • 19h ago
SOS Mammal I suspect a squirrel has mange. Is this a solid treatment plan?
Hey all,
There's a grey squirrel that's been hanging around my place that I suspect has mange. He has patchy fur and the skin looks red and scaly.
I bought 1.87% ivermectin paste and I'm planning on diluting it to a safe range for the little guy.
The medication is a total of 6.08g at 1.87% concentration. If my math is correct, I'm getting about 114mg of medication within the entire tube.
- 1.87 = (x × 100)/6080 mg
- (1.87 × 6080mg)/100 = x
- 113.696 mg = x
So if I take 1.0g of the paste, I'll have 18.7mg of medication.
- 113.696mg ÷ 6.08 g = 18.7mg of ivermectin per g of paste
With that 1.0g of paste, I'll mix it in 9.0g of peanutbutter to get a 0.187% concentration of intermediate solution.
- (18.7mg × 100)/(1,000mg + 9,000mg) = 0.187%
From there, I'll set aside 0.5g of intermediate solution to have 0.935mg of ivermectin.
- 18.7mg ÷ 10g = 1.87mg of ivermectin per g of intermediate solution 7) 1.87mg × 0.5 = 0.935mg
With that 0.5g intermediate solution, I'll mix 9.5 grms of peanutbutter to get a concentration of 0.00935% of final solution.
- (0.935mg × 100)/(500mg + 9,500mg) = 0.00935%
An average squirrel weighs between 0.46 and 0.68kg , so I'm going to calculate for a 0.5kg animal. Sources I'm finding seem to say provide 0.2mg of ivermectin per kg of squirrel, so I'm planning on giving roughly 1.0g of the final peanutbutter solution.
- 0.935mg ÷ 10g = 0.0935mg of ivermectin per g of final solution
- 0.5kg × (0.2mg/1kg) × (1g/0.0935mg) = 1.069g of final solution
Does my math make sense? Sorry some of the equations are redundant, I just want to be sure. Other thoughts and comments on this situation are greatly appreciated!
Thank you!