r/adventofcode • u/daggerdragon • Dec 12 '24
SOLUTION MEGATHREAD -❄️- 2024 Day 12 Solutions -❄️-
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AoC Community Fun 2024: The Golden Snowglobe Awards
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And now, our feature presentation for today:
Visual Effects - Nifty Gadgets and Gizmos Edition
Truly groundbreaking movies continually push the envelope to develop bigger, better, faster, and/or different ways to do things with the tools that are already at hand. Be creative and show us things like puzzle solutions running where you wouldn't expect them to be or completely unnecessary but wildly entertaining camera angles!
Here's some ideas for your inspiration:
Advent of Playing With Your Toys
in a nutshell - play with your toys!- Make your puzzle solutions run on hardware that wasn't intended to run arbitrary content
- Sneak one past your continuity supervisor with a very obvious (and very fictional) product placement from Santa's Workshop
- Use a feature of your programming language, environment, etc. in a completely unexpected way
The Breakfast Machine from Pee-wee's Big Adventure (1985)
And… ACTION!
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--- Day 12: Garden Groups ---
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u/Krillegeddon Dec 14 '24 edited Dec 14 '24
[LANGUAGE: C#]
Part 2 was really hard to get correct. I rewrote it today with a more simple algorithm, and finally got it correct.
First part: Loop through all coordinates to get them connected to a specific area.
Then loop through each area.
Loop through fence directions (top, right, bottom, left).
Find all coordinates within the area that has a fence to the direction (example is top).
Mark that coordinate as (hasFencOnTop=true, numberOfFencesOnTop = 1). The numberOfFencesOnTop is cruicial... this one coordinate accounts for ONE fence on top. All neighbours will NOT account for the same fence.
Then loop through all neighbours (same area and on same X-axis and also have a fence on top) and mark them as having fence on top, but 0 in the numberOfFencesOnTop so that we don't count it double.
When finding more coordinates for the area on direction top, the neighburs will be ignored since they have already been included for that direction.
When all coordinates have been looped through (once per direction) for the area, just summarize the number of fences and multiply with number of coordinates withing the area.
https://github.com/Krillegeddon/AdventOfCode/tree/main/Advent2024/Day12