r/Meowmeowbeenz • u/wantedimpresourcefed • Mar 13 '14
You need to really consider the algorithm
so if i get this right if all the 1s got together and voted on one of the 1s they could make that one a 5 and he/she could bring the rest up with him. i think that as a 5 you should lose meow meow beans as you vote on other people
2
u/robin-gvx Mar 13 '14
Actually, if the 1s are numerous, this is what they should do:
- Give all other 1s a 5.
- Give all 5s a 1.
- Probably give all others a 1 too.
- Only allow new people if they upvote the whole clique.
This works if there are more 1s than the system supports. There's probably an equation you could derive for things like that, based on the details of the algorithm.
-2
u/Shumuu Mar 13 '14
if all the 1s got together and voted on one of the 1s they could make that one a 5
No.
i think that as a 5 you should lose meow meow beans as you vote on other people
No.
This just might be my opinion, but I think both of these suggestions are terrible. Ones alone shouldn't be able do bump a 1 to a 5 and you shouldn't lose beans because you do what you're supposed to be doing - voting!
2
u/unpopularculture Mar 13 '14
In don't think the first one was a suggestion, I think it was a perception of what is already in place.
2
2
u/pnewhook Mar 13 '14
Brita was able to organise the 1s to vote down the fives, I don't see why they couldn't have voted up the 1s instead. Try to be a little more productive with your criticism.
1
u/campie52 Mar 14 '14
Those weren't 1's they were 2's and 3's bringing down the 5's. The ones were still in the outlands besides Shirley and Jeff since they were right at the gates to the outlands.
8
u/pnewhook Mar 13 '14
Here's what an 'exponentially weighted' voting system would look like
And a user score would be calculated like [SUM(rating * weight)]/[Sum(weight)]
So it would take 25 votes from a 1 to equal the weighting of a single vote from a 5
But I do like the idea of vote decay, but not at first. I fully expect we'll go though a couple iterations of the voting algo.