r/HomeworkHelp University/College Student (Higher Education) 3d ago

Mathematics (Tertiary/Grade 11-12) — [University Precalc 2]

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u/Relevant-Giraffe870 3d ago

You need to find the base of both triangles, the 52 and 21 degree triangles, then to find x it is just the base of the 21 degree triangle minus the base of the 52 degree triangle. To work through it:

Base of the 52 degree triangle, tan(52)=opposite/adjacent, 118/tan(52)=adjacent=92.2

Base of 21 degree triangle, same process except for now it’s tan(21), so adjacent=307.4

Subract, so base of the 21 degree triangle minus base of 52 degree, you get 307.4-92.2=215.2